2^(2X) - 5 x 2^(X) + 6 = 0
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Originally Posted by stepho_145 2^(2X) - 5 x 2^(X) + 6 = 0 For simplicity, lets substitute 2^x with y Now anti-substitute
Last edited by angel.white; April 8th 2008 at 09:47 PM.
Originally Posted by stepho_145 2^(2X) - 5 x 2^(X) + 6 = 0 Let . Then this equation becomes Can you factor this? (By the way, I strongly discourage the use of "x" as a multiplication symbol at this point in your education. It looks too much like the variable x. You can use the * for multiplication if you need a symbol.) -Dan
Originally Posted by stepho_145 2^(2X) - 5 x 2^(X) + 6 = 0 put , then your quadratic becomes: which obviously factorises to: or reversing the substitution: RonL
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