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Math Help - Solving for critical value

  1. #1
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    Solving for critical value

    Don't even know where to start,

    -x-2x(1-lnx) = 0
    x^4

    Thank you
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  2. #2
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    Quote Originally Posted by stepho_145 View Post
    Don't even know where to start,

    -x-2x(1-lnx) = 0
    x^4

    Thank you
    \Rightarrow -x - 2x (1 - \ln x) = 0

    \Rightarrow -x(1 + 2[1 - \ln x]) = 0

    \Rightarrow -x(3 - 2 \ln x) = 0

    \Rightarrow x = 0 or 3 - 2 \ln x = 0 ......
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