1. ## Quadratic Formula

(a) Use the quadratic formula to solve the distance formula
for in terms of the other quantities. (The quadratic formula gives you two solutions, enter the larger one first.)
(b) Substitute and into the above formula and find
(c) Now check your answer to (a) is correct by plugging in the values for and from (b) and seeing if your formula gives

2. Originally Posted by lilikoipssn
(a) Use the quadratic formula to solve the distance formula
for in terms of the other quantities. (The quadratic formula gives you two solutions, enter the larger one first.)
(b) Substitute and into the above formula and find
(c) Now check your answer to (a) is correct by plugging in the values for and from (b) and seeing if your formula gives
the quadratic formula says, the solutions in x to the quadratic equation $ax^2 + bx + c = 0$ are given by:

$x = \frac {-b \pm \sqrt{b^2 - 4ac}}{2a}$

you want to solve: $\frac 12at^2 + ut - s = 0$ for t. just follow the formula

3. ## Ok

Originally Posted by lilikoipssn
(a) Use the quadratic formula to solve the distance formula

for in terms of the other quantities. (The quadratic formula gives you two solutions, enter the larger one first.)
(b) Substitute and into the above formula and find
(c) Now check your answer to (a) is correct by plugging in the values for and from (b) and seeing if your formula gives
Applying the quadratic formula we get $t=\frac{-u\pm\sqrt{u^2-4\cdot{\frac{1}{2}a}\cdot{-s}}}{2\cdot{\frac{1}{2}a}}$