Quadratic Formula

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April 8th 2008, 03:58 PM
lilikoipssn

Quadratic Formula

(a) Use the quadratic formula to solve the distance formula
http://homework.math.ucsb.edu/webwor...76ade2eeb1.png
for http://homework.math.ucsb.edu/webwor...5b59f2bc11.png in terms of the other quantities. (The quadratic formula gives you two solutions, enter the larger one first.)
(b) Substitute http://homework.math.ucsb.edu/webwor...73ece9ebf1.png and http://homework.math.ucsb.edu/webwor...21878f2f31.png into the above formula and find http://homework.math.ucsb.edu/webwor...eba1435051.png
(c) Now check your answer to (a) is correct by plugging in the values for http://homework.math.ucsb.edu/webwor...973887cab1.png and http://homework.math.ucsb.edu/webwor...fd8fbc7ea1.png from (b) and seeing if your formula gives http://homework.math.ucsb.edu/webwor...afaf9e4c51.png
April 8th 2008, 04:05 PM
Jhevon

Quote:

Originally Posted by lilikoipssn

(a) Use the quadratic formula to solve the distance formula
http://homework.math.ucsb.edu/webwor...76ade2eeb1.png
for http://homework.math.ucsb.edu/webwor...5b59f2bc11.png in terms of the other quantities. (The quadratic formula gives you two solutions, enter the larger one first.)
(b) Substitute http://homework.math.ucsb.edu/webwor...73ece9ebf1.png and http://homework.math.ucsb.edu/webwor...21878f2f31.png into the above formula and find http://homework.math.ucsb.edu/webwor...eba1435051.png
(c) Now check your answer to (a) is correct by plugging in the values for http://homework.math.ucsb.edu/webwor...973887cab1.png and http://homework.math.ucsb.edu/webwor...fd8fbc7ea1.png from (b) and seeing if your formula gives http://homework.math.ucsb.edu/webwor...afaf9e4c51.png

the quadratic formula says, the solutions in x to the quadratic equation $ax^2 + bx + c = 0$ are given by:

$x = \frac {-b \pm \sqrt{b^2 - 4ac}}{2a}$

you want to solve: $\frac 12at^2 + ut - s = 0$ for t. just follow the formula
April 8th 2008, 04:05 PM
Mathstud28

Ok

Quote:

Originally Posted by lilikoipssn

(a) Use the quadratic formula to solve the distance formula
http://homework.math.ucsb.edu/webwor...76ade2eeb1.png

for http://homework.math.ucsb.edu/webwor...5b59f2bc11.png in terms of the other quantities. (The quadratic formula gives you two solutions, enter the larger one first.)
(b) Substitute http://homework.math.ucsb.edu/webwor...73ece9ebf1.png and http://homework.math.ucsb.edu/webwor...21878f2f31.png into the above formula and find http://homework.math.ucsb.edu/webwor...eba1435051.png
(c) Now check your answer to (a) is correct by plugging in the values for http://homework.math.ucsb.edu/webwor...973887cab1.png and http://homework.math.ucsb.edu/webwor...fd8fbc7ea1.png from (b) and seeing if your formula gives http://homework.math.ucsb.edu/webwor...afaf9e4c51.png

Applying the quadratic formula we get $t=\frac{-u\pm\sqrt{u^2-4\cdot{\frac{1}{2}a}\cdot{-s}}}{2\cdot{\frac{1}{2}a}}$