Thread: sin 2x - sin x/2

Hi!


It´s been some time since I last did trigonometric equations.
I dont remember if I should know this or not, but anyway, right now I dont.

f(x)= sin 2x - sin x/2 is periodic with what period?

Just point me in a direction, thanks!

Hello,

We know that sinus is 2pi-periodic.

sin(X+2pi)=sin(X)

sin(2x) -> find t such as sin(2(x+t))=sin(2x)
sin(2(x+t))=sin(2x+2t)=sin(2x)

This means that 2t=2pi -> t=pi

Do the same for sin(x/2) and finding t' such as sin((x+t')/2)=sin(x/2)

The period of the function will be gcd(t,t')

I dont get it, pretty much nothing =)

Well, i'm sorry, i really can't explain more :'(

Well...

sin x -> sin (x + n*2pi) where n is a whole number

so sin 2x -> sin 2(x + n*2pi) correct?

gives -> sin (2x + n*4pi) correct?

so sin 2x is periodic with 4pi?

No, you can't...

so sin 2x -> sin 2(x + n*2pi)

What does that mean ?

The periodicity of a function is defined as : h(x+t)=h(x)

Suppose that f(x)=sin(x) and g(x)=2x

Here, sin(2x)=f(g(x))=h(x)

So you have to find t such as h(x+t)=h(x)

If you replace, it makes :

So you have to find t as i told you above : such as

sin(2x+2pi)=sin(2x)

So t=pi works

Originally Posted by Moo

Hello,

We know that sinus is 2pi-periodic.

sin(X+2pi)=sin(X)

sin(2x) -> find t such as sin(2(x+t))=sin(2x)
sin(2(x+t))=sin(2x+2t)=sin(2x)

This means that 2t=2pi -> t=pi

Do the same for sin(x/2) and finding t' such as sin((x+t')/2)=sin(x/2)

The period of the function will be gcd(t,t')

very nice method... by the way, it is "sine" not "sinus"

Grmbl !
Ok, one more thing to learn ^^