Itīs been some time since I last did trigonometric equations.
I dont remember if I should know this or not, but anyway, right now I dont.
f(x)= sin 2x - sin x/2 is periodic with what period?
Just point me in a direction, thanks!
We know that sinus is 2pi-periodic.
sin(2x) -> find t such as sin(2(x+t))=sin(2x)
This means that 2t=2pi -> t=pi
Do the same for sin(x/2) and finding t' such as sin((x+t')/2)=sin(x/2)
The period of the function will be gcd(t,t')
No, you can't...
What does that mean ?so sin 2x -> sin 2(x + n*2pi)
The periodicity of a function is defined as : h(x+t)=h(x)
Suppose that f(x)=sin(x) and g(x)=2x
So you have to find t such as h(x+t)=h(x)
If you replace, it makes :
So you have to find t as i told you above : such as
So t=pi works