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Math Help - anybody help this problem

  1. #1
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    anybody help this problem

    The average of a, b and c is 56. The average of b, c and d is 42. What is the value of (a d)?

    (A) 98

    (B) 42

    (c) 36

    (D) 28

    ( E ) 14
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  2. #2
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    Quote Originally Posted by sri340 View Post
    The average of a, b and c is 56. The average of b, c and d is 42. What is the value of (a d)?

    (A) 98

    (B) 42

    (c) 36

    (D) 28

    ( E ) 14
    \frac{a + b + c}{3} = 56 \implies a + b + c = 168

    \frac{b + c + d}{3} = 42 \implies b + c + d = 126

    I can get you a - d. Is that what you needed?
    (a + b + c) - (b + c + d) = 168 - 126

    a - d = 42

    -Dan
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