How would I solve this 3x2(righthand corner) - 2xy+ 2y2(righthand corner)

x-y(under the problem)

sorry if im like leaching off for help but I really don't understand ;/

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- Jun 10th 2006, 12:43 PM #1

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- Jun 10th 2006, 10:46 PM #2

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Originally Posted by**Aarxn**

$\displaystyle \frac{3x^2-2xy+2y^2}{x-y}$.

1. This is an expression and can't be "solved", you would need and equation

if you want a solution (also a single equation in two variables does not

generally have a unique solution).

2. You could be asking for this to be simplified, but then this looks to me

about as simplified as you are going to get.

One supposed simplification could rearrange this as:

$\displaystyle

\frac{3x^2-2xy+2y^2}{x-y}=3x+y+\frac{3y^2}{x-y}

$,

but if anything this is more complicated than what you started with.

RonL

- Jun 23rd 2006, 06:42 PM #3

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I agree that the algebraic fraction cannot be solved. I also agree that the most likely question asked would be to simplify the fraction.

If that was the case then one could proceed by factorising the numerator and denominator in turn to obtain similar factors(top & bottom) which can then be cancelled.

However the question cannot be simplified due to terms given.

beens