Hi can anybody show me how to find x?
-180= -90 - tan^-1 (x/16) - tan^-1 (x/200)
There is no alebraic way I am away of but you could do this... Say $\displaystyle f(x)=90-arctan\bigg(\frac{x}{16}\bigg)-arctan\bigg(\frac{x}{200}\bigg)$ then we want $\displaystyle f(x)=0$...I would graph...or use the intermediate value theorem...or just use a graphing calculator
Hello,
This is straaaaaaaaaaaaaange
90=arctan(x/16)+arctan(x/200)
If we compose with tan, we have :
tan(90)=tan(arctan(x/16)+arctan(x/200))
But tan(90)= infinity :'(
We can find somewhere the general formula for tan(a+b). I haven't looked further, maybe there is a solution though.
He is right I am so used to putting cookie cutter responses to find the x...since $\displaystyle tan\bigg(\frac{\pi}{2}\bigg)=\infty$ and the image of $\displaystyle arctan(x)$ is $\displaystyle \bigg(\frac{-\pi}{2},\frac{\pi}{2}\bigg)$...therefore there is no solutions..that is unless this is in radians and not degrees? wait once again...I didnt look at this...I didnt read it right...sory