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Thread: Adding factors

  1. #1
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    Smile Adding factors

    Here i have part of a question which im unsure about.

    Ive been given this: x^2 + 2x(m+1) + (m-3)(m+1) and i have to add the two factors.

    How should i go about it?

    Thank u in advance
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  2. #2
    Bar0n janvdl's Avatar
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    Quote Originally Posted by steph_r View Post
    Here i have part of a question which im unsure about.

    Ive been given this: x^2 + 2x(m+1) + (m-3)(m+1) and i have to add the two factors.

    How should i go about it?

    Thank u in advance
    $\displaystyle x^2 + 2x(m+1) + (m-3)(m+1)$

    Factorise.

    $\displaystyle x^2 + (m+1)(2x + (m - 3))$

    Is this what you meant?
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  3. #3
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    Quote Originally Posted by janvdl View Post
    $\displaystyle x^2 + 2x(m+1) + (m-3)(m+1)$

    Factorise.

    $\displaystyle x^2 + (m+1)(2x + (m - 3))$

    Is this what you meant?
    In the answers it came up with 2m - 2 i.e the coefficient of x ???
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  4. #4
    Bar0n janvdl's Avatar
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    Quote Originally Posted by steph_r View Post
    Here i have part of a question which im unsure about.

    Ive been given this: x^2 + 2x(m+1) + (m-3)(m+1) and i have to add the two factors.

    How should i go about it?

    Thank u in advance

    $\displaystyle Let (m+1) = k $

    $\displaystyle x^2 + 2xk + (m - 3)k$

    But:
    $\displaystyle m - 3 = (m + 1) - 4$


    $\displaystyle x^2 + 2xk + (k - 4)k $


    $\displaystyle x^2 + 2xk + k^2 - 4k$


    $\displaystyle x^2 + 2x(k - 2) + k^2$


    But:
    $\displaystyle k = m+1$

    $\displaystyle x^2 + 2x(m + 1 - 2) + (m + 1)^2$

    $\displaystyle x^2 + 2x(m - 1) + (m + 1)^2$

    $\displaystyle x^2$ + x(2m - 2) + $\displaystyle (m + 1)^2$


    Is this what you wanted?
    Last edited by janvdl; Apr 7th 2008 at 03:59 AM. Reason: Forgot math tags.
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