Adding factors

**steph_r** · April 7th 2008, 02:25 AM

Here i have part of a question which im unsure about.

Ive been given this: x^2 + 2x(m+1) + (m-3)(m+1) and i have to add the two factors.

How should i go about it?

Thank u in advance

**janvdl** · April 7th 2008, 02:30 AM

Originally Posted by steph_r

Here i have part of a question which im unsure about.

Ive been given this: x^2 + 2x(m+1) + (m-3)(m+1) and i have to add the two factors.

How should i go about it?

Thank u in advance

$x^2 + 2x(m+1) + (m-3)(m+1)$

Factorise.

$x^2 + (m+1)(2x + (m - 3))$

Is this what you meant?

**steph_r** · April 7th 2008, 03:07 AM

Originally Posted by janvdl

$x^2 + 2x(m+1) + (m-3)(m+1)$

Factorise.

$x^2 + (m+1)(2x + (m - 3))$

Is this what you meant?

In the answers it came up with 2m - 2 i.e the coefficient of x ???

**janvdl** · April 7th 2008, 03:48 AM

Originally Posted by steph_r

Here i have part of a question which im unsure about.

Ive been given this: x^2 + 2x(m+1) + (m-3)(m+1) and i have to add the two factors.

How should i go about it?

Thank u in advance

$Let (m+1) = k$

$x^2 + 2xk + (m - 3)k$

But:
$m - 3 = (m + 1) - 4$

$x^2 + 2xk + (k - 4)k$

$x^2 + 2xk + k^2 - 4k$

$x^2 + 2x(k - 2) + k^2$

But:
$k = m+1$

$x^2 + 2x(m + 1 - 2) + (m + 1)^2$

$x^2 + 2x(m - 1) + (m + 1)^2$

$x^2$ + x(2m - 2) + $(m + 1)^2$

Is this what you wanted?

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