Originally Posted by
gumi A framer wants to enclose a rectangular field by a fence divide it into two smaller rectangular fields by constructing another fence parallel to one side of the field.
The farmer has 3000 yards of fencing. Find the dimension of the field so that total enclosed area is a maximum. (hint let h be the height and w be the width)
then 3h+2w=3000 You want to maximize the area hw. If you solve for h in terms of w then substitute into the expression hw, you get a quadratic function (you could just as well solve for w in terms of h) Find the maximum of quadratic using one of three techniques)