how would you simplfy the square root of 124
when you simplify the square root of 125 you can have 5 squareroots of 3
taht is what i mean
Find the biggest factor of 124 that is a perfect square and use the property that: $\displaystyle \sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}$
Also, $\displaystyle \sqrt{125} \neq 5\sqrt{3}$. Using what I told you above:
$\displaystyle \sqrt{125} = \sqrt{25 \cdot 5} = \sqrt{25} \cdot \sqrt{5} = 5 \sqrt{5}$
Ah ok Moo beat me.