Ive got a problem and my maths test is 2mw! gaaaaaa
The roots of the equation X^2 + (P-10)X = 10P are a and a + 4 . Find the possible values of P
a is actually the aplha sign thingy but i dunno how to type it
Well, if you have a trinomial :
ax˛+bx+c=0, and two roots of the equation, you have :
and
Here, a=1, b=P-10, c=-10P,
And just replace ^^
The system to solve will be :
The first equation will give :
Then replace it in the second equation to get P
Sorry, i didn't understand the title as i should have