Thread: hai help plz

One kind of hard candy sells for 89 cent per kilogram. Another sells for $1.10
per kilogram. How many kilograms of each kind will be used for 30 kilograms of a mixture to sell for 96 cent per kilogram?


How many millileters of vinegar must be added to 20 milliters of a 10%-vineger solution to make it a 25% vinegar solution?

How would I solve these?

Originally Posted by Aarxn

One kind of hard candy sells for 89 cent per kilogram. Another sells for $1.10
per kilogram. How many kilograms of each kind will be used for 30 kilograms of a mixture to sell for 96 cent per kilogram?

Let us say you sell kilograms of candy which goes for .89 and kilograms of candy which goes for 1.10 then the total price is,

and the total amout is,

In this equation solve for "y",
thus, substitute that into the first equation,

Open parantheses,

Subtract 33 from both sides and combine "x" terms,

Divide both sides by (-.21) thus,
thus,

Originally Posted by Aarxn

How many millileters of vinegar must be added to 20 milliters of a 10%-vineger solution to make it a 25% vinegar solution?

Here is the formula,


You have 20 milliletrs of 10% vineger solution. Meaning 10% of 20 is vineger thus, 2 milliletrs of vineger. You add millileters to get a concentration of 25% meaning,

Note, and understand why the numerator is the way it is and the denominator is the way is it.

Now cross mutiply considering .25 as a fraction 1/4 thus,

Thus,

Subtract 8 and m from both sides,

Thus,
need to be added.

Originally Posted by ThePerfectHacker

Here is the formula,


You have 20 milliletrs of 10% vineger solution. Meaning 10% of 20 is vineger thus, 2 milliletrs of vineger. You add millileters to get a concentration of 25% meaning,

Note, and understand why the numerator is the way it is and the denominator is the way is it.

Now cross mutiply considering .25 as a fraction 1/4 thus,

Thus,

Subtract 8 and m from both sides,

Thus,
need to be added.

Hey, thank you for helping me.