Results 1 to 5 of 5

Math Help - Quadratic Equat & Functions

  1. #1
    Junior Member
    Joined
    May 2006
    Posts
    38

    Question Quadratic Equat & Functions

    My problem I have is on shapes which I get really confused on in story type problems and trying to understand how to get the quadratic equation to be able to fit the story and to solve it?

    The problem:

    The hypotenuse of a right triangle is 6 feet long. One leg is 2 feet shorter than the other. Find the lengths of the legs and round to the nearest tenth of a foot.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member
    earboth's Avatar
    Joined
    Jan 2006
    From
    Germany
    Posts
    5,829
    Thanks
    123
    Quote Originally Posted by kbryant05
    ...
    The problem:
    The hypotenuse of a right triangle is 6 feet long. One leg is 2 feet shorter than the other. Find the lengths of the legs and round to the nearest tenth of a foot.
    Hello,

    let x be the longer of the two legs, then the shorter leg is (x-2). (All mesures in feet).
    By the rule of Pythagoras you can calculate:

    x^2+(x-2)^2=6^2

    Expand the LHS of your equation (be aware that you have to use the binomial formula!) and subtract 36 on both sides. You'll get:

    2x^2-4x-32=0

    Use the formula to solve this equation. The negative solution isn't very plausible with your problem. So you have:
    x=1+\sqrt{17}\ \approx\ 5.1'

    Greetings

    EB
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Junior Member
    Joined
    May 2006
    Posts
    38

    Can you show the second part?

    thank you for being so very quick ... are you able to show me the second part of the equation for the other leg? They have 3.1 feet as an answer and I am not getting it? I'm a little lost. Sorry I'm just a farm girl who isn't very good with these types of problems.
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Super Member
    earboth's Avatar
    Joined
    Jan 2006
    From
    Germany
    Posts
    5,829
    Thanks
    123
    Quote Originally Posted by kbryant05
    thank you for being so very quick ... are you able to show me the second part of the equation for the other leg? They have 3.1 feet as an answer and I am not getting it? I'm a little lost. Sorry I'm just a farm girl who isn't very good with these types of problems.
    Hello,

    as I've posted above the longer leg is 5.1', so the shorter leg must be 5.1' - 2' = 3.1'.

    Greetings

    EB
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Junior Member
    Joined
    May 2006
    Posts
    38

    Sorry

    I'm so sorry I was working on another problem at the same time and should have paid better attention. Thank you for such a fine job!!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. quadratic functions
    Posted in the Algebra Forum
    Replies: 4
    Last Post: May 2nd 2010, 10:04 PM
  2. Quadratic Functions
    Posted in the Algebra Forum
    Replies: 1
    Last Post: January 15th 2010, 03:10 AM
  3. quadratic functions
    Posted in the Algebra Forum
    Replies: 4
    Last Post: November 23rd 2009, 01:35 PM
  4. Quadratic Functions
    Posted in the Algebra Forum
    Replies: 16
    Last Post: July 27th 2009, 10:11 AM
  5. Quadratic functions
    Posted in the Algebra Forum
    Replies: 3
    Last Post: November 14th 2007, 05:11 PM

Search Tags


/mathhelpforum @mathhelpforum