ok this question hopefully will not take long, I do not understand this question at all.
Express 3+2√75/
3-√12
in the form a+b√3 where a,b e(the symbol meaning is a member of in replace of the e) R\{0}
first off please be more careful with how you denote things...I am assuming your question is simplify $\displaystyle \frac{3+2(75)^{\frac{1}{2}}}{3-(12)^{\frac{1}{2}}}$if so what you must first do is simplfiy the radicals since $\displaystyle (75)^{\frac{1}{2}}=(3*5^2)^{\frac{1}{2}}$ you can rewrite it as $\displaystyle 5(3)^{\frac{1}{2}}$ and using the same method $\displaystyle (12)^{\frac{1}{2}}=2(3)^{\frac{1}{2}}$ so this whole thing is equal to $\displaystyle \frac{3+10(3)^{\frac{1}{2}}}{3-2(3)^{\frac{1}{2}}}$ now I am sure you can go from there...ill tell you the answer its $\displaystyle -12(3)^{\frac{1}{2}}-23$
Answered in the thread http://www.mathhelpforum.com/math-he...256-surds.html