How do I find the constant term in ((-x)^3+(-3/x))^24 ?
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Originally Posted by weasley74 How do I find the constant term in ((-x)^3+(-3/x))^24 ? for yours we get This should get you started. I have to go
Last edited by TheEmptySet; April 3rd 2008 at 12:07 PM. Reason: La tex error
I've tried using this, but I get the wrong answer in the end..
You need the term such that: (Ax^3)^a*(Bx^-1)^(24-a) is constant. This is only satisfied when a = 6 Hence the constant term is: (-1)^6*(-3)^18*(24 choose 6)
I'm back here is how you finish. Sinc ewe want the constant term we want the exponent on the x to be zero. solving the equation we can generate the constant term using k=18
thanks! got it now! =)
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