3 5
_ + _
2y 2y
Since denominators are equal, we can just add the numerator:
$\displaystyle \frac {3}{2y} + \frac {5}{2y}$
$\displaystyle \frac {(3 + 5)}{2y}$ <---- Add numerators
$\displaystyle \frac {8}{2y}$
$\displaystyle \frac {8}{2}$ reduces down to $\displaystyle \frac {4}{1}$
so we have:
$\displaystyle \frac {4}{y}$
No more worries ever for you:
http://www.mathhelpforum.com/math-he...tml#post124198