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Thread: Logarithm as inverse

  1. #1
    Newbie north1224's Avatar
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    Exclamation Logarithm as inverse

    Write the inverse of each function.

    Please show work and short explanation so I understand how to get the answers for the rest of my homework

    1) $\displaystyle Y=2^{x/3}$

    2) $\displaystyle Y=log_{5} X^2$


    Also If I Need to solve for Y in the following what is the answer for the following (please show work):

    $\displaystyle f(x)=log_4(x+4)-3$
    $\displaystyle X= -2$
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  2. #2
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    Quote Originally Posted by north1224 View Post
    Also If I Need to solve for Y in the following what is the answer for the following (please show work):

    $\displaystyle f(x)=log_4(x+4)-3$
    $\displaystyle X= -2$

    well lets say you have $\displaystyle log_{base} number$. This is equivalent to $\displaystyle log_{x} number / log_{x} base$ with x being whatever you want.....10 for calculating purposes

    so

    $\displaystyle f(x)=log_4(x+4)-3 $
    $\displaystyle x =2 $

    $\displaystyle f(x)=log_4(2+4)-3 $
    $\displaystyle f(x)=log_4(6) -3 $
    $\displaystyle f(x)=(log_{10}(6) / log_{10}(4) ) -3 $
    $\displaystyle f(x)=~1.2925 - 3 = -1.7075$
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