4t+12

_____

t^2-9

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- Apr 2nd 2008, 12:04 PMimbadatmathsimplifying each rational expression
4t+12

_____

t^2-9 - Apr 2nd 2008, 12:10 PMtopher0805
**1.)**$\displaystyle 4t+12$

Factor out the common terms. In this case, the only common term is 4:

$\displaystyle

4(t+3)$

**2.)**$\displaystyle t^2-9$

Recognize this as a difference of squares to get:

$\displaystyle (t+3)(t-3)$ - Apr 2nd 2008, 12:29 PMimbadatmath
Thank you so much, but i am just clarifying this is the final answer

4(t+3)

________

(t+3)(t-3) - Apr 2nd 2008, 12:56 PMtopher0805
Yes those are the final answers. I am a bit confused. Was it two questions like I did or was it supposed to be like this:

$\displaystyle

\frac {4(t+3)}{(t+3)(t-3)}$

If it was one question and it is a division statement, then you can also cancel out the (t+3) terms to get a final answer of:

$\displaystyle

\frac {4}{t-3}$ - Apr 2nd 2008, 01:13 PMimbadatmath
it was all one question i am not sure how to write it liek u do

4t+12

_____

t^2-9