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Math Help - solve the equations

  1. #1
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    solve the equations

    im soooo lost any help would be amazing
    1.
    (x) (x) (1)
    _ - _ = ___
    (6) (8) (12)



    2.

    (4) (-2a)
    ___ = ___

    (a-7) (a+3)


    3.

    (x) (5) (1)
    ___ + ___ = ____
    (x+1) (x) (x^2+x)
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  2. #2
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    i dont know why it does not look right but the () are grouped so its like the first groupe is part of the first fraction and so on
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  3. #3
    Bar0n janvdl's Avatar
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    Quote Originally Posted by imbadatmath View Post
    im soooo lost any help would be amazing
    1.
    (x) (x) (1)
    _ - _ = ___
    (6) (8) (12)
    \frac{x}{6} - \frac{x}{8} = \frac{1}{12}

    Multiply every term by 24

    4x - 3x = 2

    x = 2

    Quote Originally Posted by imbadatmath View Post
    2.

    (4) (-2a)
    ___ = ___

    (a-7) (a+3)
    \frac{4}{a-7} = \frac{-2a}{a+3}

    Multiply every term with  (a - 7)(a + 3)

    4(a+3) = (-2a)(a-7)

    4a + 12 = -2a^2 + 14a

    2a^2 - 10 + 12 = 0

    2(a^2 - 5 + 6) = 0

    2(a - 3)(a - 2) = 0

    Thus x = 3 or x = 2


    Quote Originally Posted by imbadatmath View Post
    3.

    (x) (5) (1)
    ___ + ___ = ____
    (x+1) (x) (x^2+x)
    First notice that (x^2 + x) = (x)(x + 1). Always factorise!

    Now multiply every term by (x)(x + 1).

    (x)(x) + (5)(x+1) = 1

    x^2 + 5x + 5 - 1 = 0

    x^2 + 5x + 4 = 0

    (x + 4)(x + 1) = 0

    Thus x = -4 or x = -1
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