Hello, I am new to these forums. After hitting a wall on my take-home quiz, I am on the hunt for some assistance. Our professor told us we can use any means necessary to get help, so I am doing just that! Always been terrible at word problems, algebra in general for that matter. Have two problems here that left me with nothing but a blank paper and a nasty migraine!
1. The area of a rectangle is 80 meters^2 (squared). The length is six more than twice its width. Find the length and width.
2. The profit P, generated for a video store is given by the equation p = x^2 - 15x - 50, where X indicates the number of videos sold. How many videos must be sold for the profit to be $200?
Thanks in advance!
We know A since it is given, so plug that into the formula:
Now we have two variables, but lets get it down to one so that we can actually solve for something. How do length and width relate to eachother? Well we were told that length is 6 more than twice the width, so L = 6+2W
Now we can substitute this value in for L
Solve by factoring (Hint: -40 = -5*8)
This will give you two solutions (use the positive answer since you can't have negative width).
Then plug that answer into the equation again and solve for length.
Now you just factor it (hint: -250 = -25 * 10)
This will give you two solutions, evaluate which makes the most sense (hint: it doesn't make sense to sell negative videos)
I don't even know what the question was, I just copied Mr. Fantastic's answer and changed the variable letters. I don't even know what you just posted, I'm just randomly hitting keys right now, I don't even know what I'm typing!