1. ## Logarithimiccs

2 Problems I need help on

Log(5)2/Log(5)X=X/LogX

and

Log4Log(2)X=1

both solved without a calculator

2. I'm confused about your notation. Is this what you mean for the first one? $\displaystyle \frac{\log_{5}2}{\log_{5}x}=\frac{x}{\log x}$?

3. yes it is

4. Originally Posted by scfan000
2 Problems I need help on

Log(5)2/Log(5)X=X/LogX

and

Log4Log(2)X=1

both solved without a calculator
I think you will have to adopt a clearer notation here.

I'm guessing here, do you intend that

$\displaystyle Log(5)2=\log_5(2)$ ?

Then do you intend that $\displaystyle LogX$ denote the common (log to base 10)
or natrural log of $\displaystyle X$?

I am also mystified by what you want "Log4Log(2)X" to represent.

Might I suggest that you use "log_n(x)" to denote the log to the base
n of x, be explicit in all instances about the base, and rewrite your questions
accordingly?

RonL

5. Originally Posted by Jameson
I'm confused about your notation. Is this what you mean for the first one? $\displaystyle \frac{\log_{5}2}{\log_{5}x}=\frac{x}{\log x}$?

To solve:

$\displaystyle \frac{\log_{5}2}{\log_{5}x}=\frac{x}{\log x}$,

first turn it upside down (this is a personal preference, it can be done this way up):

$\displaystyle \frac{\log_{5}(x)}{\log_{5}(2)}=\frac{\log(x)}{x}$,

then apply the change of base rule for logs to the left hand side to reduce
the all the logs to the same base as that on the right hand side.

RonL

6. i c it now. and i can figure out the problem from there
sry about the notation. i just don't quite know how to yet

7. ## haj

You need to solve:
Log(5)2/Log(5)X=X/LogX