Math Help - algebra

1. algebra

Any help is greatly appreciated
1.

20a^2b 12xy^3
______ * ______

3xy 5ab^2

2. is solved

a^2-1 6+15a
_____ * ______

2+5a 3-3a

2. $\frac{a^2 - 1}{2+5a} * \frac {6+15a}{3-3a}$

$\frac{(a + 1)(a - 1)}{2 + 5a} * \frac{3(2 + 5a)}{3(1 - a)}$

cancel (2 + 5a) and cancel 3

$\frac {(a + 1)(a - 1)}{(1 - a)}$

$\frac {(a + 1)(a - 1)}{-(a - 1)}$

cancel (a - 1)

$-(a + 1)$

3. Never mind you changed somethign and thanks

what do you mean when you say frac?

my LaTex was coded incorrectly. Go back and check it out now.

Any help is greatly appreciated
1.

20a^2b 12xy^3
______ * ______

3xy 5ab^2
$\frac {20ba^2}{3xy} * \frac{12xy^3}{5ab^2}$

20/5 = 4 and 12 / 3 = 4, so we have:

$\frac{4ba^2}{xy} * \frac {4xy^3}{ab^2}$

One of each variable a,b, and is reduced, and the x's cancel, therefore,

$\frac{16ay^2}{b}$

6. thank you agian