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Math Help - algebra

  1. #1
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    algebra

    Any help is greatly appreciated
    1.

    20a^2b 12xy^3
    ______ * ______

    3xy 5ab^2


    2. is solved

    a^2-1 6+15a
    _____ * ______

    2+5a 3-3a
    Last edited by imbadatmath; March 31st 2008 at 11:17 AM.
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  2. #2
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    \frac{a^2 - 1}{2+5a} * \frac {6+15a}{3-3a}

    \frac{(a + 1)(a - 1)}{2 + 5a} * \frac{3(2 + 5a)}{3(1 - a)}

    cancel (2 + 5a) and cancel 3

    \frac {(a + 1)(a - 1)}{(1 - a)}

    \frac {(a + 1)(a - 1)}{-(a - 1)}

    cancel (a - 1)

    -(a + 1)
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  3. #3
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    Never mind you changed somethign and thanks
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  4. #4
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    Quote Originally Posted by imbadatmath View Post
    what do you mean when you say frac?

    my LaTex was coded incorrectly. Go back and check it out now.
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  5. #5
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    Quote Originally Posted by imbadatmath View Post
    Any help is greatly appreciated
    1.

    20a^2b 12xy^3
    ______ * ______

    3xy 5ab^2
    \frac {20ba^2}{3xy} * \frac{12xy^3}{5ab^2}

    20/5 = 4 and 12 / 3 = 4, so we have:

    \frac{4ba^2}{xy} * \frac {4xy^3}{ab^2}

    One of each variable a,b, and is reduced, and the x's cancel, therefore,

    \frac{16ay^2}{b}
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  6. #6
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    thank you agian
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