# Math Help - Tough linear equations in 2 variable question, can you solve it :)

1. ## Tough linear equations in 2 variable question, can you solve it :)

SOLVE :-

(3x +2y - 7)^2 +(5x + 7y - 13)^2 = 0, for real values of x and y

2. Originally Posted by ice_syncer
SOLVE :-

(3x +2y - 7)^2 +(5x + 7y - 13)^2 = 0, for real values of x and y

Since squares are always greater than or equal to zero, this equation will only have a solution when each of the squares are equal to zero.

So we need to solve the system.

$3x+2y-7=0$

$5x+7y-13=0$

Try either elimination or substition

I got

$x=\frac{23}{11} \mbox{ and }y=\frac{4}{11}$