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Math Help - Tough linear equations in 2 variable question, can you solve it :)

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    Thumbs down Tough linear equations in 2 variable question, can you solve it :)

    SOLVE :-

    (3x +2y - 7)^2 +(5x + 7y - 13)^2 = 0, for real values of x and y


    well, I'm not bad at maths, it's that this question is too challenging, so please HELP HELP HELP !!!!!
    Last edited by ice_syncer; March 31st 2008 at 08:41 AM.
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  2. #2
    Behold, the power of SARDINES!
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    Quote Originally Posted by ice_syncer View Post
    SOLVE :-

    (3x +2y - 7)^2 +(5x + 7y - 13)^2 = 0, for real values of x and y


    well, I'm not bad at maths, it's that this question is too challenging, so please HELP HELP HELP !!!!!
    Since squares are always greater than or equal to zero, this equation will only have a solution when each of the squares are equal to zero.

    So we need to solve the system.

    3x+2y-7=0

    5x+7y-13=0

    Try either elimination or substition

    I got

    x=\frac{23}{11} \mbox{ and }y=\frac{4}{11}
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