# Thread: HELP! I'm new and I need help with factorisation :(

1. ## HELP! I'm new and I need help with factorisation :(

I'm finding this topic quite difficult, and have homework in for tomorrow relating to it and was wondering if you could help?
I've figured some out, but some seem to be a bit trickier than others, so I was just wondering if you could make sure that the ones I have already done are correct, and the ones I haven't done, help me a little?
This section is about expanding brackets and these are the ones I have done so far:

(x+4)(x+2) = x²+6x+8
(p+3)(p+4) = p²+7x+12
(d-2)(d+5) = d²+3d-10
(f-2)(f-6) = f²-8f+12
And I need help with these:
(x+2)² = ?
(2x+3)(x-2) = ?
(3y+2)(2y-3)= ?

The next section is about factorisation and I don't understand it at all, so all help is greatly appreciated :

5ab+2b = ?
4pq+q = ?
7ty+10y = ?
3xz+5x²z = ?
11ab-7bc = ?
p²+3p = ?
2x²+xy = ?
4p²+6pq = ?

If you can guide me towards the answers, or even give me answers.. it's all appreciated. thanks!

2. Hello,

All the previous are correct

(x+2)² = ?
(x+2)²=(x+2)(x+2)

There is a general formula : (a+b)²=a²+2ab+b²

(2x+3)(x-2) = ?
(3y+2)(2y-3)= ?
I don't understand how you could do the previous ones and why you can't do these oO

In general :

For the first one for example :
(2x+3)(x-2)=2x(x-2)+3(x-2)=2x²-4x+3x-6=2x²-x-6.

Now, try to do the second one.

The next section is about factorisation and I don't understand it at all, so all help is greatly appreciated :
When you go to factorise, always look for a common factor.

If you have ab+cb, then the factorisation will be b(a+c)

5ab+2b = ?
4pq+q = ?
7ty+10y = ?
3xz+5x²z = ?
= 3(xz)+5x(xz)

11ab-7bc = ?
p²+3p = ?
p²+3p=p*p+3p

2x²+xy = ?
4p²+6pq = ?
The same as above

² means that you multiply twice the same number.

3. thank you!