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Math Help - Help. Can't figure this out.

  1. #1
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    Help. Can't figure this out.

    I need help finding what x equals. I know logs have something to do with it. I just need to know what to do first.

    x(1.22)^2 = 450
    x(1.22)^7 = 1250
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  2. #2
    o_O
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    What would logs have to do with it? Divide both sides by the coefficient and solve for x? Unless you mistyped something ...

    x(1.22)^{2} = 450
    x = \frac{450}{1.22^{2}} ??
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  3. #3
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    I did that and I get like 302 for the first one and 310 for the 2nd. I think the x value needs to be the same for both.
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  4. #4
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    Quote Originally Posted by o_O View Post
    What would logs have to do with it? Divide both sides by the coefficient and solve for x? Unless you mistyped something ...

    x(1.22)^{2} = 450
    x = \frac{450}{1.22^{2}} ??
    This solution is inconsistent with the other equation.

    Quote Originally Posted by XxmotleyxX View Post
    I need help finding what x equals. I know logs have something to do with it. I just need to know what to do first.

    x(1.22)^2 = 450
    x(1.22)^7 = 1250
    As posted, these equations are inconsistent and therefore have no solution. They are essentially saying that (1.22)^2 = 1250/450 which is clearly false.
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  5. #5
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by XxmotleyxX View Post
    I need help finding what x equals. I know logs have something to do with it. I just need to know what to do first.

    x(1.22)^2 = 450
    x(1.22)^7 = 1250
    I should get you on a double post here. It is a good idea to keep your posts on a single problem together in one thread. It makes for better consistency.

    -Dan
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  6. #6
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    no. they are both part of the same problem.
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  7. #7
    Senior Member Twig's Avatar
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    XxMotleyXX are you REALLY SURE that your 1.22 value is correct?
    I read your other post about the same problem...
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  8. #8
    Forum Admin topsquark's Avatar
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    I am redirecting this thread to here.

    Thread closed.

    -Dan
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