# Thread: Help. Can't figure this out.

1. ## Help. Can't figure this out.

I need help finding what x equals. I know logs have something to do with it. I just need to know what to do first.

x(1.22)^2 = 450
x(1.22)^7 = 1250

2. What would logs have to do with it? Divide both sides by the coefficient and solve for x? Unless you mistyped something ...

$\displaystyle x(1.22)^{2} = 450$
$\displaystyle x = \frac{450}{1.22^{2}}$ ??

3. I did that and I get like 302 for the first one and 310 for the 2nd. I think the x value needs to be the same for both.

4. Originally Posted by o_O
What would logs have to do with it? Divide both sides by the coefficient and solve for x? Unless you mistyped something ...

$\displaystyle x(1.22)^{2} = 450$
$\displaystyle x = \frac{450}{1.22^{2}}$ ??
This solution is inconsistent with the other equation.

Originally Posted by XxmotleyxX
I need help finding what x equals. I know logs have something to do with it. I just need to know what to do first.

x(1.22)^2 = 450
x(1.22)^7 = 1250
As posted, these equations are inconsistent and therefore have no solution. They are essentially saying that (1.22)^2 = 1250/450 which is clearly false.

5. Originally Posted by XxmotleyxX
I need help finding what x equals. I know logs have something to do with it. I just need to know what to do first.

x(1.22)^2 = 450
x(1.22)^7 = 1250
I should get you on a double post here. It is a good idea to keep your posts on a single problem together in one thread. It makes for better consistency.

-Dan

6. no. they are both part of the same problem.

7. XxMotleyXX are you REALLY SURE that your 1.22 value is correct?