SOLVE FOR X IN TERMS OF LOGA AND LOGB

a^(x-3) = b^(2x)

SO CONFUSED SOMEONE HELP ME!!!

Printable View

- Mar 27th 2008, 11:49 AMclp_53Solve For X In Terms Of Loga And Logb
SOLVE FOR X IN TERMS OF LOGA AND LOGB

a^(x-3) = b^(2x)

SO CONFUSED SOMEONE HELP ME!!! - Mar 27th 2008, 12:12 PMcolby2152
$\displaystyle a^{x-3}=b^{2x}$

Take the log of both sides...

$\displaystyle \log(a^{x-3})=\log(b^{2x})$

The exponents get knocked down outside of the log as coefficients...

$\displaystyle \log(a)(x-3)=\log(b)(2x)$

You can surely solve the rest with a calculator for the logs and algebra for the variable solution!