# Solve For X In Terms Of Loga And Logb

• March 27th 2008, 12:49 PM
clp_53
Solve For X In Terms Of Loga And Logb
SOLVE FOR X IN TERMS OF LOGA AND LOGB

a^(x-3) = b^(2x)

SO CONFUSED SOMEONE HELP ME!!!
• March 27th 2008, 01:12 PM
colby2152
Quote:

Originally Posted by clp_53
SOLVE FOR X IN TERMS OF LOGA AND LOGB

a^(x-3) = b^(2x)

SO CONFUSED SOMEONE HELP ME!!!

$a^{x-3}=b^{2x}$

Take the log of both sides...

$\log(a^{x-3})=\log(b^{2x})$

The exponents get knocked down outside of the log as coefficients...

$\log(a)(x-3)=\log(b)(2x)$

You can surely solve the rest with a calculator for the logs and algebra for the variable solution!