Math Help - Factor the following polynomial completely

1. Factor the following polynomial completely

8x^2-32

2. Hello,

You can note that 32 is 4x8

So factorize.

Then, you'll have something in the form a²-b². You know that you can factorize it into (a+b)(a-b)

3. would it be (8x+8)(x-4)

4. Nope,

$8x^2-32=8(x^2-4)$

As $x^2-4=x^2-2^2$, $x^2-4=(x-2)(x+2)$

You're asked to factorise, so don't develop 8 to the brackets :-)

5. how am i suposed to know when to break things up in to the () or to factor and how ia m confused on how to get the final answer or which set of numbers you gave me is the final answer

6. I don't like to give the entire solution directly, so i give the elements...

If you want it... :

$8x^2-32=8*x^2-4*8=8(x^2-4)=8(x^2-2^2)=8(x-2)(x+2)$