8x^2-32
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Hello, You can note that 32 is 4x8 So factorize. Then, you'll have something in the form aČ-bČ. You know that you can factorize it into (a+b)(a-b)
would it be (8x+8)(x-4)
Nope, $\displaystyle 8x^2-32=8(x^2-4)$ As $\displaystyle x^2-4=x^2-2^2$, $\displaystyle x^2-4=(x-2)(x+2)$ You're asked to factorise, so don't develop 8 to the brackets :-)
how am i suposed to know when to break things up in to the () or to factor and how ia m confused on how to get the final answer or which set of numbers you gave me is the final answer
I don't like to give the entire solution directly, so i give the elements... If you want it... : $\displaystyle 8x^2-32=8*x^2-4*8=8(x^2-4)=8(x^2-2^2)=8(x-2)(x+2)$
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