Hi!

(e^x)^2 - 5e^x + 6 = 0

how should I start?

I tried setting e^x = y

then -> y^2 - 5y + 6 = 0

solving this I get the roots 3 and 2

Am I doing this wrong?

UH ok =) I just found out this -> I get answers y=3 and y=2 .. I take e^x = 3 and e^x = 2

then I take ln 3 and ln 2 and I get the correct answer.

Just as a note.

What are the common situations for using the method of calling e^x = y ?

thanks!