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Thread: Quick question thread

  1. #1
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    Question Quick question thread

    I'll use this thread for quick small questions that come up while I'm studying.

    is $\displaystyle \frac{b}{b+7}$ the same as $\displaystyle \frac{1}{7}$ ?
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  2. #2
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    Hello,

    What do you mean as "the same" ?

    If you try to find b such as this equation is verified, you'll find 7=1, which means that there is no solution.
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  3. #3
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    well if $\displaystyle b = \frac{7}{6}$ yes, otherwise no.
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    Is $\displaystyle \frac{2}{2+7}$ the same as $\displaystyle \frac{1}{7}$?
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  5. #5
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    Wooops, i did a little mistake >_<
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    I'm a bit confused, is there anything else I can do to reduce $\displaystyle
    \frac{b}{b+7}
    $ more?

    Can I divide $\displaystyle b$ from the numerator and the denominator and obtain
    $\displaystyle \frac{1}{1+7} \rightarrow \frac{1}{8}$ ?
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  7. #7
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    Please answer the question I asked, where b=2.
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  8. #8
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    Quote Originally Posted by Plato View Post
    Please answer the question I asked, where b=2.
    Sorry, I just realized $\displaystyle \frac{b}{b+7}$ is not the same as $\displaystyle \frac{1}{7}$, but can it be reduced to $\displaystyle \frac{1}{8}$?
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  9. #9
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    Quote Originally Posted by norifurippu View Post
    I'm a bit confused, is there anything else I can do to reduce $\displaystyle
    \frac{b}{b+7}
    $ more?

    Can I divide $\displaystyle b$ from the numerator and the denominator and obtain
    $\displaystyle \frac{1}{1+7} \rightarrow \frac{1}{8}$ ?
    NO! IT CAN'T!

    That is the conclusion the earlier posts are trying to steer you towards!!

    Try putting in some values of b (apart from b = 1). Do you get 1/8?? Answer Plato's question: If b = 2, is $\displaystyle \frac{2}{2+7}$ the same as $\displaystyle \frac{1}{7}$? What about when b = 3? etc.

    When you divide the top and bottom of a fraction by something, ALL of the top and ALL of the bottom get divided by that something.
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  10. #10
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    Quote Originally Posted by mr fantastic View Post
    When you divide the top and bottom of a fraction by something, ALL of the top and ALL of the bottom get divided by that something.
    Thanks, that's what I hadn't completely understood, if I divide $\displaystyle \frac{b}{b+7}$ by b, I get $\displaystyle \frac{1}{1+\frac{7}{b}}$, not $\displaystyle \frac{1}{7}$ or $\displaystyle \frac{1}{8}$.

    Phew... this got longer than I thought, thank you everybody for the help.
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  11. #11
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    Quote Originally Posted by norifurippu View Post
    Thanks, that's what I hadn't completely understood, if I divide $\displaystyle \frac{b}{b+7}$ by b, I get $\displaystyle \frac{1}{1+\frac{7}{b}}$, not $\displaystyle \frac{1}{7}$ or $\displaystyle \frac{1}{8}$.

    [snip]
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