Thread: [SOLVED] Eponential Equations

I need to solve for x in the equation:
9^(2x+1)=81(27^2)
I've tried various things, getting every answer but the correct one, which is 2. I have no idea how x=2 though.
Here's one of my (futile) tries:
9^(2x+1)=9^2(27^x)
x+1=27^x
1 = (27^xx)
Guidance through the proper steps would be appreciated, thank you!

Originally Posted by ria3

I need to solve for x in the equation:
9^(2x+1)=81(27^2)
I've tried various things, getting every answer but the correct one, which is 2. I have no idea how x=2 though.
Here's one of my (futile) tries:
9^(2x+1)=9^2(27^x)
x+1=27^x
1 = (27^xx)
Guidance through the proper steps would be appreciated, thank you!

So:
x

Put everything as powers of 3:

=
=
therefore:

Sorry for the strange powers, I'm still trying to get the hang of this math code stuff. =)

thank you!