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Math Help - Stumped on a math problem

  1. #1
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    Stumped on a math problem

    I really can't solve this ...I'm lost because of the pie.....the problem is:


    4/3(pie)x r to the third power
    r=8.43


    wasn't sure how to do the symbols for the problem sorry
    Last edited by ambergarrett955; March 19th 2008 at 04:04 PM. Reason: left something out
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  2. #2
    Behold, the power of SARDINES!
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    Quote Originally Posted by ambergarrett955 View Post
    I really can't solve this ...I'm lost because of the pie.....the problem is:


    4/3(pie)x r to the third power



    wasn't sure how to do the symbols for the problem sorry
    \pi \approx 3.14 so depending on your value of r you would just multiply. For example if r =2

    \frac{4}{3} \cdot \pi \cdot 2^3=\frac{4}{3} \cdot 3.14 \cdot 8 \approx 33.49\

    I hope this helps.
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  3. #3
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    Seems to me you are writing down the formula for the volume of a sphere with a radius of r = 8.43.

    Well pi (not pie ) is about 3.14, so you can stick a 3.14 in wherever you see pi, and stick a fork in wherever you see pie.

    So the volume of your sphere is: \frac{4}{3}(3.14)(8.43)^3

    Just multiply those numbers together.
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  4. #4
    Behold, the power of SARDINES!
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    Quote Originally Posted by ambergarrett955 View Post
    I really can't solve this ...I'm lost because of the pie.....the problem is:


    4/3(pie)x r to the third power
    r=8.43


    wasn't sure how to do the symbols for the problem sorry

    <br />
\frac{4}{3} \cdot \pi \cdot (8.43)^3=\frac{4}{3} \cdot 3.14 \cdot 599 \approx 2508.1\<br />
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