# Thread: Stumped on a math problem

1. ## Stumped on a math problem

I really can't solve this ...I'm lost because of the pie.....the problem is:

4/3(pie)x r to the third power
r=8.43

wasn't sure how to do the symbols for the problem sorry

2. Originally Posted by ambergarrett955
I really can't solve this ...I'm lost because of the pie.....the problem is:

4/3(pie)x r to the third power

wasn't sure how to do the symbols for the problem sorry
$\pi \approx 3.14$ so depending on your value of r you would just multiply. For example if r =2

$\frac{4}{3} \cdot \pi \cdot 2^3=\frac{4}{3} \cdot 3.14 \cdot 8 \approx 33.49\$

I hope this helps.

3. Seems to me you are writing down the formula for the volume of a sphere with a radius of $r = 8.43$.

Well pi (not pie ) is about 3.14, so you can stick a 3.14 in wherever you see pi, and stick a fork in wherever you see pie.

So the volume of your sphere is: $\frac{4}{3}(3.14)(8.43)^3$

Just multiply those numbers together.

4. Originally Posted by ambergarrett955
I really can't solve this ...I'm lost because of the pie.....the problem is:

4/3(pie)x r to the third power
r=8.43

wasn't sure how to do the symbols for the problem sorry

$
\frac{4}{3} \cdot \pi \cdot (8.43)^3=\frac{4}{3} \cdot 3.14 \cdot 599 \approx 2508.1\
$