Thread: rational exponents

I need to simplify (49c^6)^(-5/2) down to 1/(343c^9) but I'm not sure how to do this. The same goes for (27a^3b^3)^(2/3). I find it much easier to simplify when they are in the form of x^a/n. Now, with all the new letters, i'm sort of confused. Any tips would be appreciated... thank you!

Originally Posted by ria3

I need to simplify (49c^6)^(-5/2) down to 1/(343c^9) but I'm not sure how to do this. ...

First: I assume that there is typo and you mean:



In the attached pdf-file you'll find most of the rules concerning calculations of powers. Use it to do the other questions.