look..........................here is a problem where you

need to find a method to find a number 33 by using

5,3,3,3,6,2

you may use any of the formulae or the signs(+,-,*,/)

thanks!

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- Mar 19th 2008, 03:44 AM #1

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- Mar 19th 2008, 06:38 AM #2

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Hello, pickbrain!

This one has too many possibilities . . .

Find 33 by using {2, 3, 3, 3, 5, 6} and (+, -, ×, ÷)

. . . . $\displaystyle (2 \times 3 \times 5) + \frac{3+6}{3}$

. . . . $\displaystyle (3 \times 3 \times 5) - (2 \times 3 + 6)$

. . . . $\displaystyle (3-2) \times 3 \times 6 + (3 \times 5) $

. . . . $\displaystyle 6^2 - \left(5 - 3 + \frac{3}{3}\right)$

- Apr 25th 2008, 06:54 AM #3

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- Apr 27th 2008, 08:26 AM #4

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I think this one is wrong, as theres only one 6 in the given set, 6^2=6*6,..so..

Btw very true, too many ways, such as (6*5)+3,..unless uve got to use all numbers, which i dont think so

Edit 3 : Soroban, ur using the 2 as a power, but it doesnt really suit the (+,-,*,/) does it ?