1. ## think....33

look..........................here is a problem where you
need to find a method to find a number 33 by using

5,3,3,3,6,2
you may use any of the formulae or the signs(+,-,*,/)

thanks!

2. Hello, pickbrain!

This one has too many possibilities . . .

Find 33 by using {2, 3, 3, 3, 5, 6} and (+, -, ×, ÷)

. . . . $(2 \times 3 \times 5) + \frac{3+6}{3}$

. . . . $(3 \times 3 \times 5) - (2 \times 3 + 6)$

. . . . $(3-2) \times 3 \times 6 + (3 \times 5)$

. . . . $6^2 - \left(5 - 3 + \frac{3}{3}\right)$

3. Originally Posted by Soroban
Hello, pickbrain!

This one has too many possibilities . . .

. . . . $(2 \times 3 \times 5) + \frac{3+6}{3}$

. . . . $(3 \times 3 \times 5) - (2 \times 3 + 6)$

. . . . $(3-2) \times 3 \times 6 + (3 \times 5)$

. . . . $6^2 - \left(5 - 3 + \frac{3}{3}\right)$
But Carol Vorderman still has better legs than Soroban

(for non-UK residence: This is a reference to the TV show Countdown, on which Carol Vordermam was the lighting calculator eye-candy who solved these problems to show the contestants how it should have been done)

4. Originally Posted by Soroban
Hello, pickbrain!

This one has too many possibilities . . .

. . . . $6^2 - \left(5 - 3 + \frac{3}{3}\right)$

I think this one is wrong, as theres only one 6 in the given set, 6^2=6*6,..so..

Btw very true, too many ways, such as (6*5)+3,..unless uve got to use all numbers, which i dont think so

Edit 3 : Soroban, ur using the 2 as a power, but it doesnt really suit the (+,-,*,/) does it ?