1. ## linear problem

the number of brownies N that the chess club sells during the fundraiser depends on the price x that they are sold for according to the equation
N = -500x + 2000

graph the equation on the axis to the left (x goes from 2 - 10 in incriments of 2, y goes from 0 - 5000 in incriments of 1000)

b) what is the largest number of brownies that can be sold

c) write a formula for the total amount of money M that the club makes if they sell brownies at price X

2. Recall that the standard form of the equation of a line is:

$\displaystyle y = mx + b$

You have:

$\displaystyle N = -500x + 2000$

So, your slope is -500 and your y-intercept is 2,000. Draw a dot at the point (0,2000). Then place a dot at the point (1, 1500), and one at (2, 1000) all the way until it reaches the x-axis.

The largest number of brownies is simply the highest point on the graph, which happens to be 2,000. If the brownies are sold for $0, then 2,000 brownies will be sold. The total amount of money is equal to the amount of brownies sold multiplied by the price.$\displaystyle M = NX\$