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Math Help - logarithms please help

  1. #1
    spensersievers
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    logarithms please help

    solve for x
    log(x-1)=log(x+2)-log(x+2)
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  2. #2
    Member SengNee's Avatar
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    Quote Originally Posted by spensersievers View Post
    solve for x
    log(x-1)=log(x+2)-log(x+2)
    \log{(x-1)}=\log{(x+2)}-\log{(x+2)}
    \log{(x-1)}=\log{\frac{(x+2)}{(x+2)}}
    \log{(x-1)}=\log{1}
    x-1=1
    x=2

    \log{(x-1)}=\log{(x+2)}-\log{(x+2)}
    \log{(x-1)}=0
    x-1=1
    x=2

    I also feel bizarre.
    Last edited by SengNee; March 18th 2008 at 09:34 PM.
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  3. #3
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by spensersievers View Post
    solve for x
    log(x-1)=log(x+2)-log(x+2)
    The right hand side is rather bizarre, are you sure that is copied correctly?

    -Dan
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