Factor $\displaystyle 4x^2-4x-80$

My answer: $\displaystyle 4(x+4)(x-5)$

Do I have the correct answer?

Thank you in advance!

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- Mar 18th 2008, 03:27 PMmt_lapinFactoring - another problem
Factor $\displaystyle 4x^2-4x-80$

My answer: $\displaystyle 4(x+4)(x-5)$

Do I have the correct answer?

Thank you in advance! - Mar 18th 2008, 03:30 PMiknowone
Yes. A good way to check is to take your answer and do the reverse of factoring. Multiply it all out and see if you recover what you started with.

- Mar 18th 2008, 03:31 PMrualin
You should never ask if your factoring is right since you can always multiply out and check. (Yes)

- Mar 18th 2008, 03:31 PMmt_lapin
Okay. Thanks!