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Math Help - Simplifying radical expressions?

  1. #1
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    Simplifying radical expressions?

    Im stuck on this question:

    \frac{2x^2-x-6}{2x^2+3x-2} division \frac{x^2-9}{x^2-x-6} X \frac{4x^2-4x+1}{2x^2-5x+2}
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  2. #2
    Senior Member topher0805's Avatar
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    Remember that when you are working with fractions, division can be expressed as such:

    \frac {a}{b}\div \frac {c}{d} = \frac {a}{b}\cdot \frac {d}{c}

    Now just multiply everything out, then factor out common terms.
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  3. #3
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    hmm..i still don't get what to do. Do i flip over the last fraction? And switch the X into a division sign?
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  4. #4
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    Quote Originally Posted by eh501 View Post
    Im stuck on this question:

    \frac{2x^2-x-6}{2x^2+3x-2} division \frac{x^2-9}{x^2-x-6} X \frac{4x^2-4x+1}{2x^2-5x+2}
    Let a=\frac{2x^2-x-6}{2x^2+3x-2}, b=\frac{x^2-9}{x^2-x-6}, and c=\frac{4x^2-4x+1}{2x^2-5x+2}

    I'm taking your problem to be \frac{a}{b \times c} If so, you can use topher0805's suggestion and rewrite this as a \times ( \frac{1}{b \times c}) or you can simplify b x c first then work from there. Either way, you're just gonna have to do some algebra.

    Can you get it started?
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