Im stuck on this question:
$\displaystyle \frac{2x^2-x-6}{2x^2+3x-2}$ division $\displaystyle \frac{x^2-9}{x^2-x-6}$ X $\displaystyle \frac{4x^2-4x+1}{2x^2-5x+2}$
Let $\displaystyle a=\frac{2x^2-x-6}{2x^2+3x-2}$, $\displaystyle b=\frac{x^2-9}{x^2-x-6}$, and $\displaystyle c=\frac{4x^2-4x+1}{2x^2-5x+2}$
I'm taking your problem to be $\displaystyle \frac{a}{b \times c}$ If so, you can use topher0805's suggestion and rewrite this as $\displaystyle a \times ( \frac{1}{b \times c})$ or you can simplify b x c first then work from there. Either way, you're just gonna have to do some algebra.
Can you get it started?