# uhh i forgot how to do this =/..

• Mar 18th 2008, 02:38 PM
eh501
uhh i forgot how to do this =/..
Here's the problem:

If $9x^3+3x^2$ is divided by $3x^2,$ the quotient is

3x

6x

3x+1

6x+1

Please don't just tell me the answer, i also want to know how to do it.
• Mar 18th 2008, 02:42 PM
topher0805
$
\frac {9x^3+3x^2}{3x^2} = \frac {9x^3}{3x^2} + \frac {3x^2}{3x^2}
$

Factor a 3 out of everything:

$
\frac {3x^3}{x^2} + \frac {x^2}{x^2}$

Factor an $x^2$ out of everything:

Can you solve it from here?
• Mar 18th 2008, 02:56 PM
eh501
Quote:

Originally Posted by topher0805
$
\frac {9x^3+3x^2}{3x^2} = \frac {9x^3}{3x^2} + \frac {3x^2}{3x^2}
$

Factor a 3 out of everything:

$
\frac {3x^3}{x^2} + \frac {x^2}{x^2}$

Factor an $x^2$ out of everything:

Can you solve it from here?

The answer is C right? Wow i feel like an idiot, that was such an easy question and i just didn't feel like reading the whole questions correctly. I should read the question better more often.
• Mar 18th 2008, 02:58 PM
topher0805
Yes the answer is C. Sometimes putting the question down for a few minutes then coming back to it can help. Never underestimate the power of a fresh pair of eyes.