Hello everyone, I'm in need of a bit of help.
Could someone please explain the process of finding the discriminants and the number of real solutions to the quadratic equation of this expression:
For the polynomial , the discriminant is given as: . There are 3 cases in the value the discriminant can have and each tell you something about your quadratic/parabola:
- The quadratic has two real roots (crosses x-axis twice)
- The quadratic has exactly one real root (crosses x-axis once)
- The quadratic has no real roots (never crosses x-axis)
Thank you so much, both of you.
I understand it now!
But lets pretend that the Discriminants IS a positive number, how would I know how many Real Solutions there are?
I have one more quick question totally unrelated while I have you here:
I'm terrible at Simplifying Square Roots.
Could you explain how to simplify this expression for me?
(not sure how to do the square root symbol on here)
Assume that all variables represent positive real numbers.
Thanks again!
Okay, I think I'm starting to get it, but could you explain to me where each of the 'parts' come from on this expression:
Also,
Is there another way to write that without powers as fractions?
I can't use fractions in my answer.
All variables represent positive real numbers.
Should I just turn them into decimals?
?