Please help me solve cubed sq root of 625 over cubed sq root of 5
It's called a "cube root" not a "cubed square root."
$\displaystyle \frac{\sqrt[3]{625}}{\sqrt[3]{5}}$
$\displaystyle = \frac{\sqrt[3]{125 \cdot 5}}{\sqrt[3]{5}}$
$\displaystyle = \frac{\sqrt[3]{5^3 \cdot 5}}{\sqrt[3]{5}}$
$\displaystyle = \frac{5~\sqrt[3]{5}}{\sqrt[3]{5}}$
$\displaystyle = 5$
-Dan