# Math Help - Radicals

Please help me solve cubed sq root of 625 over cubed sq root of 5

2. Originally Posted by QCBW
Please help me solve cubed sq root of 625 over cubed sq root of 5
It's called a "cube root" not a "cubed square root."
$\frac{\sqrt[3]{625}}{\sqrt[3]{5}}$

$= \frac{\sqrt[3]{125 \cdot 5}}{\sqrt[3]{5}}$

$= \frac{\sqrt[3]{5^3 \cdot 5}}{\sqrt[3]{5}}$

$= \frac{5~\sqrt[3]{5}}{\sqrt[3]{5}}$

$= 5$

-Dan