Please help me solve cubed sq root of 625 over cubed sq root of 5

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- Mar 16th 2008, 06:27 PMQCBWRadicals
Please help me solve cubed sq root of 625 over cubed sq root of 5

- Mar 16th 2008, 06:45 PMtopsquark
It's called a "cube root" not a "cubed square root."

$\displaystyle \frac{\sqrt[3]{625}}{\sqrt[3]{5}}$

$\displaystyle = \frac{\sqrt[3]{125 \cdot 5}}{\sqrt[3]{5}}$

$\displaystyle = \frac{\sqrt[3]{5^3 \cdot 5}}{\sqrt[3]{5}}$

$\displaystyle = \frac{5~\sqrt[3]{5}}{\sqrt[3]{5}}$

$\displaystyle = 5$

-Dan