Dear math forum members,
I have a problem
How many integers divisble by 7 can you find in the interval [4500, 7000] ?
Could you please give me just a hint on how to proceed?
Thank you in advance!
Hello,
Firstly, i'll note that 7000 is a multiple of 7.
So we'll start from there.
The previous multiple of 7 will be obtained by substracting 7 to 7000, and so on.
So if you divide the interval into intervals of 7 numbers, ]a;b], these interval will contain one and only one multiple of 7.
Hence you "just" have to see how many intervals of this sort there are in [4500;7000], and this number is given by (7000-4500)/7.
I know :-)
But it's as if you could restrict your study to the interval [first multiple of 7 coming after 4500 = N; 7000]
The number of multiples of 7 in [N;7000] will be (7000-N)/7 + 1 (because you count the extremity).
And this number is the same as the number of multiples of 7 in [4500;7000] because there is no multiple of 7 between 4500 and N.
So this shows that if you truncate (7000-4500)/7 by the inferior value (because (7000-4500)/7 = (7000-N)/7 + APositiveNumber) and add 1, you'll have the number you want.
This is the same as taking the superior integer of (7000-4500)/7
I don't know if it's clear enough
You can take a smaller example, such as [10;35]
Hello, Coach!
How many integers divisble by 7 can you find in the interval [4500, 7000] ?
Since every seventh number is divisible by 7,
. . there are: . of them on the interval [0, 7000]
We must eliminate the multiple that are less than 4500.
How many are there?
. . There are: . of them.
Therefore, there are: . multiples of 7 on [4500, 7000]
Coach, do you know the floor function (aka: the greatest integer function)?
The floor of x, , equals the largest integer which does exceed x.
Some examples: .
Most calculators have such a function built in.
For positive integers the number of multiples of d in is .
Thus to use a calculator to solve your problem we would calculate:
.