How would you solve(for "x"):

the square root of 4x-12 = x

I know that you could square both sides to get rid of the square root on the left side, but I don't know how to finish the problem. (Hint: The small 2's means squared. x2 means x squared.)

square root of(4x-12)2 = (x)2

4x-12 = x2

4x = x2-12

4x-x2 = -12

What do you do after the last step?