Results 1 to 4 of 4

Math Help - Grouping Common Factors

  1. #1
    !!!
    !!! is offline
    Junior Member
    Joined
    Feb 2008
    Posts
    28

    Grouping Common Factors

    How do I get from:

    to:
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Moo
    Moo is offline
    A Cute Angle Moo's Avatar
    Joined
    Mar 2008
    From
    P(I'm here)=1/3, P(I'm there)=t+1/3
    Posts
    5,618
    Thanks
    6
    Hello,

    (y^2+2y)^5 4(y-1)^3=[2(y^2+2y)^4 (y-1)^3] [2(y^2+2y)]

    (y-1)^4 5(y^2+2y)^4(2y+2)=2(y-1)^4 5(y^2+2y)^4(y+1)  = [2(y^2+2y)^4 (y-1)^3][5(y-1)(y+1)]

    And you factorize
    Follow Math Help Forum on Facebook and Google+

  3. #3
    !!!
    !!! is offline
    Junior Member
    Joined
    Feb 2008
    Posts
    28

    Red face

    Do you mind showing it step by step, because I still can't grasp it.
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Moo
    Moo is offline
    A Cute Angle Moo's Avatar
    Joined
    Mar 2008
    From
    P(I'm here)=1/3, P(I'm there)=t+1/3
    Posts
    5,618
    Thanks
    6
    (y^2+2y)^5 4(y-1)^3 = 2 \times 2 (y^2+2y)^4 (y^2+2y) (y-1)^3 = [2(y^2+2y)^4 \times (y-1)^3] \times [2 (y^2+2y)]

    (y-1)^4 5(y^2+2y)^4 (2y+2) = (y-1)^3 (y-1) 5 (y^2+2y)^4 2 (y+1) = 2 (y-1)^3 (y^2+2y)^4 (y+1)  = [2 (y^2+2y)^4 (y-1)^3] \times [5 (y-1) (y+1)]

    So the numerator will be :

    \left\{[2(y^2+2y)^4 \times (y-1)^3] \times [2 (y^2+2y)]\right\} - \left\{[2 (y^2+2y)^4 (y-1)^3] \times [5 (y-1) (y+1)]\right\}  = [2 (y^2+2y)^4 \times (y-1)^3] \times [2 (y^2+2y) - 5 (y-1) (y+1)]
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Extraction and Grouping Common Factors help!
    Posted in the Algebra Forum
    Replies: 7
    Last Post: December 5th 2010, 07:03 AM
  2. Common Factors
    Posted in the Algebra Forum
    Replies: 3
    Last Post: May 5th 2010, 03:45 AM
  3. What factors do 4,6,7 have in common
    Posted in the Algebra Forum
    Replies: 11
    Last Post: October 9th 2009, 05:02 AM
  4. Extraction and Grouping Common Factors help!
    Posted in the Algebra Forum
    Replies: 2
    Last Post: January 12th 2009, 04:57 AM
  5. Grouping polynomials to show a common factor
    Posted in the Algebra Forum
    Replies: 4
    Last Post: January 17th 2008, 06:53 PM

Search Tags


/mathhelpforum @mathhelpforum