what would be the varibles for:

-2x^2+6x-11=0

I know i use a quadratic formula but i get a negative square root and dont remember what to do next since its an imaginary number.

and

5 times 2^x+3=35

For this one i dont really get what to do first

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- May 23rd 2006, 06:57 PMtakkun0486finding the variables
what would be the varibles for:

-2x^2+6x-11=0

I know i use a quadratic formula but i get a negative square root and dont remember what to do next since its an imaginary number.

and

5 times 2^x+3=35

For this one i dont really get what to do first - May 23rd 2006, 07:04 PMThePerfectHackerQuote:

Originally Posted by**takkun0486**

Thus,

Thus,

Thus,

------

Ya got,

Divide by 5,

Thus,

Thus,

Same bases thus,

- May 23rd 2006, 07:08 PMtakkun0486Quote:

Originally Posted by**ThePerfectHacker**

- May 23rd 2006, 07:13 PMThePerfectHackerQuote:

Originally Posted by**takkun0486**

Anyways the problem reduces to,

Thus,

Thus,

- May 23rd 2006, 07:16 PMtakkun0486
so it was

5(2^(x+3))=35

sry that i confused you on the other parts - May 23rd 2006, 07:24 PMtakkun0486
any ideas?

- May 23rd 2006, 07:28 PMThePerfectHackerQuote:

Originally Posted by**takkun0486**

Sorry I forgot you cannot subtract, then you have,

Take logarithms,

Bring down exponent bases on rule,

Thus,

Thus,