Thread: Using the quadratic formula part 3?

Thank you to the 2 individuals who have responded to my previous post. If anyone could help me with the following 2 problems, it would greatly be appreciated.

X/(.20-X)^2 = 4.9 x 10^-4


(0.030 + 2X)^2/(0.030 - X) ^2 = 118

For the second one, instead of using the quadratic formula is it possible to square both sides and solve for X? Will this give you the exact same answer?

Thank you for any input on the above questions. Have a great day.

Originally Posted by confused20

Thank you to the 2 individuals who have responded to my previous post. If anyone could help me with the following 2 problems, it would greatly be appreciated.

X/(.20-X)^2 = 4.9 x 10^-4


(0.030 + 2X)^2/(0.030 - X) ^2 = 118

For the second one, instead of using the quadratic formula is it possible to square both sides and solve for X? Will this give you the exact same answer?

Thank you for any input on the above questions. Have a great day.

For the 2nd equation, why not take the square root of both sides?