Thread: I need help urgent please!

Originally Posted by mpgc_ac

Dear friend!
Please show me the solution of the problems below:
problem1:
Find the value of x?
if x.x.x.x=2x.x+[x]

I presume you mean,
where [ ] denotes the greatest integer function.
Then there are exactly three solutions,


.

I rather not denomstrate how I got an solution to these problem. It will take long.
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-=USER WARNED=- Do not under any conditions place threads into incorret section! What does this have ANYTHING to do with Geomtery.

Originally Posted by mpgc_ac

Dear friend!

problem 2:
find the value of x?
if x.x+y.y+w.w+z.z=x.x.x.x.x.x.x+y.y.y.y.y.y.y+w.w.w. w.w.w.w+z.z.z.z.z.z.z=0
Thank you advance.
my emial address is: sophearot@yahoo.ca

If,

Then, (assuming you are working with real numbers).

Originally Posted by ThePerfectHacker

I presume you mean,
where [ ] denotes the greatest integer function.
Then there are exactly three solutions,


.

Interesting point (at least I think so ) if [ ] denotes the nearest integer
then your third solution is correct, but from your words describing what
[ ] means in your solution it appears you want it to be the floor function.

The floor function of x is defined to be the greatest integer less than x
and is usually written .

There is a similar ceiling function defined to be the smallest integer greater
that its argument, which is usually written .

RonL

PS this question has been posted in another thread somewhere, as has the
second question in the original post (but not in the same other thread as
the first )

Originally Posted by CaptainBlack

PS this question has been posted in another thread somewhere, as has the
second question in the original post (but not in the same other thread as
the first )

I found it; interesting to note that the IP address' match between these two users. Possibly they are the same one.

Originally Posted by ThePerfectHacker

I found it; interesting to note that the IP address' match between these two users. Possibly they are the same one.

Considering that the two e-mail addresses are the same I would say it's more than likely.

-Dan