# Math Help - [Extra easy]Simplify

1. ## [Extra easy]Simplify

Hi all, really need some help with this!
I know it's super duper easy but I won't get this without a proper explenation, please help me

Okay so we are supposed to simplify this;

4a/5 * 15/2a

I think I know how to do it in theory but I just can't seem to get the right answer. Im thinking of inverting the first one and then multiplying the second one by 2 in order to get the same nominator, but it's still not right.

Just for the heck of it i'd like some help with this one aswell. It's the same thing - Simplify

2/9z * 3z^2/10

2. Originally Posted by Hanga
Hi all, really need some help with this!
I know it's super duper easy but I won't get this without a proper explenation, please help me

Okay so we are supposed to simplify this;

4a/5 * 15/2a

I think I know how to do it in theory but I just can't seem to get the right answer. Im thinking of inverting the first one and then multiplying the second one by 2 in order to get the same nominator, but it's still not right.

Just for the heck of it i'd like some help with this one aswell. It's the same thing - Simplify

2/9z * 3z^2/10
$\frac{4a}{5}*\frac{15}{2a} = \frac{60a}{10a} \Rightarrow 6$

$\frac{2}{9z}*\frac{3z^2}{10} = \frac{6z^2}{90z} \Rightarrow \frac{z}{15}$

3. Originally Posted by Hanga
Hi all, really need some help with this!
I know it's super duper easy but I won't get this without a proper explenation, please help me

Okay so we are supposed to simplify this;

4a/5 * 15/2a

I think I know how to do it in theory but I just can't seem to get the right answer. Im thinking of inverting the first one and then multiplying the second one by 2 in order to get the same nominator, but it's still not right.

Just for the heck of it i'd like some help with this one aswell. It's the same thing - Simplify

2/9z * 3z^2/10
$\frac{4a}{5} \cdot \frac{15}{2a}$

$= \frac{4a \cdot 15}{5 \cdot 2a}$

Start looking for factors common to the numerator and denominator. The most easily spotted is that variable a. We also have that 5 divides 15 evenly and 2 divides 4 evenly:
$\frac{(2 \cdot 2) \cdot a \cdot (5 \cdot 3)}{5 \cdot 2 \cdot a}$

Now cancel out the common factors:
$= \frac{2 \cdot 3}{1} = 6$

-Dan

4. thats some really fast and very good help.

THANKS ALL FOR THIS! IT HELPS ALOT!

5. Originally Posted by Hanga
thats some really fast and very good help.

THANKS ALL FOR THIS! IT HELPS ALOT!
When someone helps you, feel free to give them positive reputation or hit the thanks button under their reply.