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Thread: Help me geometric problem

  1. #1
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    Help me geometric problem

    An isosceles triangle and a rectangle share a common base . the area of the rectangle is 5 times the area of the triangle . If the area of the triangle is 60 centimeter square . and its height is 5cm .find the dimensions in centimeters of the rectangle.

    Thanks

    Sri
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  2. #2
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    The area of the triangle is $\displaystyle 60 cm^2$ and the height is $\displaystyle 5cm$ which means $\displaystyle \frac{1}{2}5b = 60$. Solving for the base length we get $\displaystyle b=24 cm$. Since the rectangle has an area 5 times that of the triangle its area is 300. But area of a rectanlge is base times height. We know the base if $\displaystyle 24 cm$ therefore the height must be $\displaystyle \frac{300}{24} = 12.5$
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